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An e.m. wave going through vacuum is den...

An e.m. wave going through vacuum is denoted by `E=E_0sin(kx-omegat)`. Which of the following is /are independent of wavelength?

A

`k`

B

`omega`

C

`k//omega`

D

`komega`

Text Solution

Verified by Experts

The correct Answer is:
c
Here, `k=2pi//lambda , omega=2piv=2pic//lambda`
So, `k/omega=(2pi//lambda)/(2piv)=1/c=constant`
So, it is independent of wavelength.
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