The electric field associated with an e.m. wave is described by the equation `E=E_0sin(4pixx10^6x-1.2pixx10^(15)t)` volt/meter, where x is in merter and t in second. The wavelength of the wave in the wave in the unit of `10^-7m` is:

Answer

`5`

Explanation

Here, `E=E_0sin(4pixx10^6x-1.2pixx10^(15)t)`
comparing it with the equation
`E=E_0sin (kx-omegat)`, we have
`k=(2pi)/lambda=4pixx10^6 or lambda=(2pi)/(4pixx10^6)`
`=5xx10^-7m`