What curvature must be given to the bounding concave surface of refracting medium `(mu = 3//2)` for a virtual image at `40 cm` of an object in this medium at a distance of `60 cm`. The adjoining medium is air `(mu = 1)`.
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Here, `R = ? Mu = 3//2, v = -40 cm, u = -60 cm, mu_(1) = 1` As refracting occurs from denser to rarer medium, therefore, ` -(mu_(2))/(u) + (mu_(1))/(v) = (mu_(1) - mu_(2))/(R )` `-(3)/(2(- 60)) + (1)/(-40) = (1 - 3//2)/(R ) , -(1)/(40) - (1)/(40) = -(1)/(2R), -(1)/(20) = -(1)/(2R) = R = 10 cm`
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