A small point objects is placed in air at a distance of `60 cm` from a convex spherical refractive surface of `mu = 1.5`. If radius of curvature of spherical surface is `25 cm`, calculate the position of the image and the power of the refracting surface.
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Here, `u = -60 cm, mu_(1) = 1, mu_(2) = 1.5, R = + 25 cm, v = ?` As refraction occurs from rarer ti denser medium, therefore `(-mu_(1))/(u) + (mu_(2))/(v) = (mu_(2) - mu_(1))/(R )` `(-1)/(-60) + (1.5)/(v) = (1.5 - 1)/(25)` `(3)/(2v) = (1)/(50) - (1)/(60) = (1)/(300)` As `v` positive, image formed on the other side of the object, i.e., in refracting denser medium at `450 cm` from the pole. Power of teh refracting surface, `P = (mu_(2) - mu_(1))/(R ) = (1.5 - 1)/(0.25) = (0.5)/(0.25) = 2 D`
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