A diverging lens of focal length `15 cm` forms an image `10 cm` from the lens. Calculate the distance of the object from the lens, given `mu = 1.5`. What is the linear magnification of the image ?
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Here, `f = - 15cm, v = -10 cm, u = ?, mu = 1.5` As `(1)/(v) - (1)/(u) = (1)/(f) :. (1)/(u) = (1)/(v) - (1)/(f) = (1)/(-10) + (1)/(15) = (-3 + 2)/(30) = (-1)/(30) :. u = -30 cm` Now, `m = (v)/(u) = (-10)/(-30) = (1)/(3)`
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