What is the apparent position of an object below a rectangular block of glass `6 cm` thick, if a layer of water `4 cm` thicke ia on the top of the glass ? Given `^(a)mu_(g) = 3//2 and ^(a)mu_(w) = 4//3`.
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Here, real depth of glass, `x_(1) = 6 cm`, real depth of water, `x_(2) = 4 cm`. `.^(a)mu_(g) = 3//2, .^(a)mu_(w) = 4//3` If `y_(1), y_(2)` are the corresponding depths, Then, `(x_(1))/(y_(1)) = .^(a)mu_(g) = (3)/(2)` `:. y_(1) = (2)/(3)x_(1) = (2)/(3) xx 6 = 4 cm` `(x_(2))/(y_(2)) = .^(a)mu_(w) = (4)/(3)` `:. y_(2) = (3)/(4)x_(2) = (3)/(4) xx 4 = 3 cm` Apparent position of the object `= (y_(1) + y_(2)) = (4 + 3)cm = 7 cm` `:.` Rise in position of the object `=(x_(1) + x_(2)) -(y_(1) + y_(2)) = (6 + 4) - (4 + 3)` ` = 10 - 7 = 3cm`
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