Refractive indices of water an glass are `4//3 and 3//2` respectively. A ray of light travelling in water is incident on the water glass interface at `30^@`. Calculate the angle of refraction.
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Here, `.^(a)mu_(g) = 4//3` and `.^(a)mu_(g) = 3//2` Refractive index of glass w.r.t. water `.^(w)mu_(g) = (.^amu_g)/(.^amu_w) = (3//2)/(4//3) = (9)/(8)` Now, in water, `I = 30^(@), r = ?` `(sin i)/(sin r) = .^(w)mu_(g) = (9)/(8)` `sin r = (8)/(9)sin i = (8)/(9)sin 30^(@) = (4)/(9) = 0.4444` `r = sin^(-1)(0.4444) = 26^(@)23'`
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