The critical angle of incidence in a glass slab placed in air is `45^(@)`. What will be yhe critical angle when the glass slab is immersed in water of refractive index `1.33` ?
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Here, `.^(a)mu_(g) = (1) /(sin C) = (1)/(sin 45^(@)) = sqrt(2) = 1.414` Refractive index of glass w.r.t. water `.^(a)mu_(g) = (.^(a)mu_(g))/(.^(a)mu_(w)) = (1.414)/(1.33)` When glass slab is immersed in water, `sin C' = (1)/(.^(w)mu_(g)) = (1.33)/(1.414) = 0.9432` ltbegt `C' = sin^(-1)(0.9432) = 70^(@)36'`
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