The refractive index of water is `4//2`. Determine the angle of the cone within which the entire outside view will be confined for a fish under water.
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As is clear from Fig. the fish can see the entire outside view within cone angle `theta = 2 C`, where `sin C = (1)/(mu) = (1)/(4//3) = 0.75` `C = sin^(-1)(0.75) = 48.7^(@)` `:. theta = 2 C = 2 xx 48.7^(@) = 97.4^(@)`
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