Calculate the critical angle for a glass air interface, if a ray of light incident in air on the surface is deviated through `15^@`, when its angle of incidence is `40^@`.
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Here, `C = ?, i = 40^(@)`, deviation, `delta = 15^(@)` As ray devitates towards normal., therefore, `r = i - delta = 40^(@) - 15^(@) = 25^(@)`. As `mu = (sin i)/(sin r) = (1)/(sin C)` `:. sin C = (sin r)/(sin i) = (sin 25^(@))/(sin 40^(@)) = (0.4226)/(0.6428) = 0.6574` `C = sin^(-1)(0.6574) = 41.1^(@)`
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