Calculate the critical angle for a glass air interface, if a ray of light incident in air on the surface is deviated through `15^@`, when its angle of incidence is `40^@`.
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Here, `I = 40^(@)` `r = 40^(@) - 15^(@) = 25^(@)` `mu = (sin i)/(sin r) = (sin 40^(@))/(sin 25^(@)) = (0.6428)/(0.4226) = 1.52` if `C` is critical angle for glass air interface, then from `sin C = (1)/(mu) = (1)/(1.52) = 0.6579` `C = sin^(-1)(0.6579) = 41.14^(@)`
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