A mark placed on the surface of a sphere is viewed through glass from a position directly opposite. If the diameter of the sphere is `10 cm` and refractive index of glass is `1.5`, find the position of the image.
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Here, `u = -10 cm, R = -5cm` `mu_(2) = 1.5, mu_(1) = 1, v = ?` In the present case, refraction occurs from denser to rarer medium. `:. (mu_(2))/(-u) + (mu_(1))/(v) = (mu_(1) - mu_(2))/(R )` `(1.5)/(10) + (1)/(v) = (1 - 1.5)/(-5) = (1)/(10)` or `(1)/(v) = (1)/(10) - (3)/(20) = -(1)/(20)` `:. v = -20 cm`
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