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Light from a point source in air falls o...

Light from a point source in air falls on a spherical glass surface `mu = 1.5 and R = 20 cm`. The image is formed at a distance of `100 cm` from the glass surface in the direction of incident light. Calculate the object distance from the centre of curvature of the spherical surface.

Text Solution

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Here, `mu_(1) = 1, mu_(2) = 1.5`,
`R = 0.2 m = 20cm, v = 100 cm, u = ?`
As refraction occurs from rarer to denser medium,
`(mu_(1))/(-u) + (mu_(2))/(v) = (mu_(2) - mu_(1))/(R )`
`(1)/(-u) + (1.5)/(100) = (1.5 - 1)/(20) = (1)/(40)`
`-(1)/(u) = (1)/(40) - (3)/(200) = (2)/(200) = (1)/(100) = -100 cm`
`:.` Distance of object from pole of spherical surface is `100 cm`
Distance of object from the centre of spherical surface ` = 100 + 20 = 120 cm`
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