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A biconvex lens has focal length (2)/(3)...

A biconvex lens has focal length `(2)/(3)` times the radius of curvature of either surface. Calculate refraction index f material of the lens.

Text Solution

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Here, `R_(1) = R, R_(2) = -R, f = (2)/(3)R`,
`mu = ?`
`(1)/(f) = (mu - 1)((1)/(R_(1)) - (1)/(R_(2)))`
`(3)/(2R) = (mu - 1) ((1)/(R) + (1)/(R )) = (mu -1) = (2)/(R )`
`:. mu -1 = (3)/(4) = 0.75, mu = 0.75 + 1 = 0.75`
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