A double convex lens made of glass of refractive index `1.56` has both radii of curvature of magnitude `20 cm`. If an object is placed at a distance of `10 cm` from this lens, find the position of image formed.
Text Solution
Verified by Experts
Here, `mu = 1.56, R_(1) = 20 cm`, `R_(2) = -20 cm, u = -10 cm, v = ?` As `(1)/(f) = (mu -1)((1)/(R_(1)) - (1)/(R_(2)))` :. `(1)/(f) = (1.56 - 1)((1)/(20) + (1)/(20)) = 0.56 xx (1)/(10)` `f = (10)/(0.56) = 17.86cm`. As `(1)/(v) - (1)/(u) = (1)/(f) :. (1)/(v) = (1)/(f) + (1)/(u) = (1)/(17.86) + (1)/(-10)` `v = -22.72 cm`
Topper's Solved these Questions
OPTICS
PRADEEP|Exercise Very short answer question|5 Videos
OPTICS
PRADEEP|Exercise very short answer questions|1 Videos
A double convex spherical glass has refractive index 1.5 and both radius of curvature 30 cm. A point object is placed at a distance of 120 cm from the spherical glass. What will be the position of the image formed ?
A double convex lens of glass of refractive index 1.6 has its both surfaces of equal radii of curvature of 30 cm each. An object of height 5 cm is placed at a distance of 12.5 cm from the lens. Calculate the size of the image formed.
The focal length of convex lens is 20 cm. If an object of height 4 cm is placed at a distance of 30 cm from the lens, find: The position of the image
A double convex thin lens made of glass (refractive index mu = 1.5 ) has both radii of curvature of magnitude 20 cm . Incident light rays parallel to the axis of the lens will converge at a distance L such that
The focal length of convex lens is 20 cm. If an object of height 4 cm is placed at a distance of 30 cm from the lens, find: The height of the image
A double convex lens is made of glass of refractive index 1.5. If its focal length is 30 cm, then radius of curvature of each of its curved surface is
A double convex lens of + 5 D is made of glass of refractive index 1.5 with both faces of equal radii of curvature. Find the value of curvature.
