A convergent beam of light passes through a diverging lens of focal length `0.2m` and comes to focus at a distance of `0.3m` behind the lens. Find the position of the point at which the beam would converge in the absence of the lens.
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Here, `f= - 0.2 m, v = +- 0.3 m` From lens equation `(1)/(v) - (1)/(u) = (1)/(f)` `(1)/(u) = (1)/(v) - (1)/(f) = (1)/(0.3) - (1)/(-0.2) = (25)/(3)` `u = (3)/(25) = 0.12 m` Therefore, in the absence of lens, the beam would converge at a distance of `0.12m` to the right of the concave lens.
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