Shows the given set up.
Here, `R = PC = 20 cm`.
`C_(1)P = 30 cm, OC_(1) = 25 cm`
As the final image due to the combination coincides with the object itself, the rays reflected from convex mirror must be retracing their path. This can happen only tend to meet at centre of curvature of convex mirror. Therefore, for convex lens,
`v = C_(1)C = C_(1)P + PC = 30 + 20 = 50 cm`,
when `u = OC_(1) = - 25 cm`.
From `(1)/(f) = (1)/(v) - (1)/(u) = (1)/(50) + (1)/(25) = (3 + 6)/(150) = (9)/(150)`
`f = 150//9 = 16.67 cm`