The power of a thin convex lens of glass is `5 dioptre`. When it is immersed in a liquid of refractive index `mu`, it behave like a diverging lens of focal length `1m`. Calculate `mu` of liquid, if `mu` of glass `= 3//2`.
Text Solution
AI Generated Solution
To solve the problem step by step, we will follow the concepts of lens optics and refractive indices.
### Step 1: Understand the given values
- The power of the thin convex lens in air is given as \( P = 5 \) diopters.
- The focal length \( f \) of the lens when immersed in a liquid is \( 1 \) meter, which means it behaves like a diverging lens in that medium.
- The refractive index of the glass lens is given as \( \mu_{glass} = \frac{3}{2} \).
### Step 2: Calculate the focal length in air
...
Topper's Solved these Questions
OPTICS
PRADEEP|Exercise Very short answer question|5 Videos
OPTICS
PRADEEP|Exercise very short answer questions|1 Videos
A thin convex lens made of glass of refractive index 3//2 has a power of 5 D. When it is immersed in a liquid of refractive index mu , it behaves like a divergent lens of focal length 1 m. Calculate the refractive index of the liquid.
A thin convergent glass lens (mu_g=1.5) has a power of +5.0D. When this lens is immersed in a liquid of refractive index mu_1, it acts as a divergent lens of focal length 100 cm. The value of mu_1 is
The power of a thin convex lens (""_(a) mu_(g)=1.5) is +5.0 D . When it is placed in liquid of refractive index ""_(a) mu_(l) then it behaves as a concavelens of focal length 100 cm. the refractive index of liquid ""_(a) mu_(i) will be
A lens is made of flint glass (refractive index =1.5 ). When the lens is immersed in a liquid of refractive index 1.25 , the focal length:
Explain what happens when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3 .
Explain what happens when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3 .
