Assertion : The focal length of an equiconvex lens placed in air to radius of curvature of either face. Reason : For an equiconvex lens radius of curvature of both the faces is same.
The focal length of an equiconvex lens is equal to radius of curvature of either surface. What is the refractive index of the material of the prism ?
The focal length of a double convex lens is equal to radius of curvature of either surface. The refractive index of its material is
Statement-1 : Focal length of an equiconvex lens of mu = 3//2 is equal to radius of curvature of each surface. Statement-2 : it follows from (1)/(f) = (mu - 1)((1)/(R_(1)) - (1)/(R_(2)))
The focal length of an equiconcave lens is 3/4 times of radius of curvature of its surfaces. find the refractive index of the material of lens. under what condition will this lens behave as a converging lens?
The focal length of equiconvex lens of retractive index, mu=1.5 and radius of curvature, R is
The focal length of a plano-convex lens is equal to its radius of curvature. The value of the refractive index of its material is
What is the focal length of double convex lens for which radius of curvature of either of the surfaces is 30 cm? [ ""_(a) mu_(g)=1.5]
The focal length of a convex lens is 10 cm and its refractive index is 1.5. If the radius of curvature of one surface is 7.5 cm , the radius of curvature of the second surface will be
The focal length of a convex lens is 10 cm and its refractive index is 1.5 . If the radius of curvature of one surface is 7.5 cm, the radius of curvature of the second surface will be :
