Why does a convex lens of glass `mu = 1.5` behave as a diverging lens when immersed in carbon disulphide of `mu = 1.65` ?
Text Solution
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To understand why a convex lens of glass (with a refractive index \( \mu = 1.5 \)) behaves as a diverging lens when immersed in carbon disulfide (with a refractive index \( \mu = 1.65 \)), we can analyze the situation using the lens maker's formula.
### Step-by-Step Solution:
1. **Understanding the Lens Maker's Formula**:
The lens maker's formula is given by:
\[
\frac{1}{f} = \left( \frac{\mu_2}{\mu_1} - 1 \right) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)
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Assertion : A convex lens of glass (mu = 1.5) behave as a diverging lens when immersed in carbon disulphinde of higher refractive index (mu = 1.65) . Reason : A diverging lens is thinner in the middle and thicker at the edges.
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