A lens whose radii of curvature are different is forming the image of an object placed on its axis. If the lens is reversed, will the position of the image change ?
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No, image will be formed at the same position. This follows from lens maker's formula : `(1)/(f) = (mu -1)((1)/(R_(1)) - (1)/(R_(2)))` When we interchange `R_(1)` and `R_(2)`, the value of `f` does not change except for the sign. Hence the image will be formed at the same position.
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