A ray of light passing through an equilateral triangular glass prism from air undergoes minimum deviation when angle of incidence is `(3)/(4) th` of the angle of prism. Calculate speed of light in prism.
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Here, `A = 60^(@), I = (3)/(4) A = (3)/(4) xx 60^(@) = 45^(@)` In the position of minimum devitation, `r = (A)/(2) = 30^(@), mu = (sin i)/(sin r) = (sin 45^(@))/(sin 30^(@)) = (1//sqrt(2))/(1//2) = sqrt(2)` As `mu = ( c)/(v), v = (c )/(mu) = (3 xx 10^(8))/(sqrt(2)) = 2.12 xx 10^(8)m//s`
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(a) If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then find the angle of incidence. (b) A ray of light passes through an equilateral prism such that the angle of emergence is equal to the angle of incidence and each is equal to 3//4^(th) of the angle of prism. Find the angle of deviation. (c) The refracting of a prism is A and the refractive index of the material of the prism is cotA//2 . Find the angle of deviation. (d) The angle of a prism is 60^@ . What is the angle of incidence for minimum deviation? The refractive index of the material of the prism is sqrt2 .
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