A prism is made of glass of unknown refractive index. A parallel beam of light is incident on a face of the prism. By rotating the prism, the minimum angle of deviation is measured to be 40^@ . What is the refractive index of the prism ? If the prism is placed in water (mu = 1.33) , predict the new angle of minimum deviation of the parallel beam. The refracting angle of prism is 60^@ .
For thin prism angle of minimum deviation( delta ) is given by
A glass prism has a refracting angle of 60^@ . The angle of minimum deviation is 40^@ . Find the refractive index. At what angle should the ray be incident so as to suffer minimum deviation ?
An equilateral glass prism of refractive index 1.5 is immersed in water. Find the angle of deviation produced when a ray of light is incident at 42^(@) on one face of the prism. (Refractive index of water = 1.33)
The angle of a glass prism is 4.5^(@) and its refractive index is 1.52. The angle of minimum deviation will be
For a prism of refractive index 1.732 , the angle of minimum deviation is equal to the angle of the prism. The angle of the prism is
When a glass prism of refracting angle 60^(@) is immersed in a liquid its angle of minimum deviation is 30^(@) . The critical angle of glass with respect to the liquid medium is
A prism is made of glass of refractive index 1.5. If the angle of minimum deviation is equal to the refracting angle of the prism, calculate the angle of the prism.
