A ray of light is incident at an angle of 60^(@) on the face of a prism with an angle of 60^(@) . Then the refractive index of the material of the prism is (the prism is in minimum deviation position)
The correct relation between the refractive index ( mu ) of the material of prism (A) and angle of minimum deviation ( delta ) is
The refractive index of the material of prism sqrt3, then the angle os minimum deviation of prism is
The refracting angle of a prism is A and refractive index of the material of the prism is cos(A//2) . The angle of minimum deviation is
The refracting angle of a prism is A and refractive index of the material of prism is cot(A//2) . The angle of minimum deviation will be
The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A//2). the angel of minimum deviation is
Calculate the refractive index of the material of an equilaterial prism for which angle of minimum deviation is 60^@ .
The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A)/(2) . The angle of minimum deviation is
The refracting angle of the prism is 60^@ and the refractive index of the material of the prism is sqrt(3) . Calculate the angle of minimum deviation in degree.