A person wears eye glasses with a power of `- 5.5 D` for distance viewing. His doctor prescribes a correction of `+ 1.5 D` for his near vision. What is the focal length of his distance viewing part of the lens and also for near vision section of the lens ?
Text Solution
AI Generated Solution
To solve the problem, we need to find the focal lengths of the lenses used for distance viewing and near vision. The power of the lenses is given, and we can use the formula relating power (P) and focal length (f):
\[ P = \frac{100}{f} \]
Where:
- \( P \) is the power in diopters (D)
- \( f \) is the focal length in centimeters (cm)
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