The focal lengths of the objective and eye piece of a compound microscope are `4 cm and 6 cm` respectively. If an object is placed at a distance of `6 cm` from the objective, calculate the magnification produced by the microscope. Take distance of distinct vision `= 25 cm`.
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Here, `f_(0) = 4 cm, f_(e) = 6 cm` `d = 25 cm, u_(0) = -6 cm, m = ?` if `v_(0)` is distance of image of object formed by the objective lens, then from `(1)/(v_(0)) - (1)/(u_(0)) = (1)/(f_(0))` `(1)/(v_(0)) = (1)/(f_(0)) + (1)/(u_(0)) = (1)/(4) + (1)/(-6) = (1)/(12)` `m = (v_(0))/(u_(0))(1 + (d)/(f_(e))) = (12)/(-6)(1 + (25)/(6)) = -2 xx (31)/(6)` `m = - 10.33`
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