An astronomical telescope consists of the thin lenses, `36 cm` apart and has a magnifying power `8`. Calculate the focal length of lenses. Two stars have an actual separation of one minute of arc. Find the angle of separation as seen through the telescope.
Text Solution
Verified by Experts
Here, `L = 36 cm, m = 8, f_(0) = ?,f_(e) = ?`, As `m = (f_(0))/(f_(e)) = 8 :. F_(0) = 8 f_(e)` Now `L = f_(0) + f_(e) = 8 f_(e) + f_(e) = 9 f_(e) = 36` `f_(e) = (36)/(9) = 4 cm f_(0) = 36 - f_(e) = 36 - 4 = 32 cm` Angle of separation as seen through telescope `= m xx` actual separation `= 8 xx 1' = 8'`
Topper's Solved these Questions
OPTICS
PRADEEP|Exercise Very short answer question|5 Videos
OPTICS
PRADEEP|Exercise very short answer questions|1 Videos
An astronomical telescope consists of two thin lenses set 36 cm apart and has a magnifying power 8. calculate the focal length of the lenses.
An astronomical telescope of magnifying power 10 consists of two thin lenses 55 cm apart. Calculate the focal length of the lenses.
An astronomical telescope of magnifying power 7 consists of two thin lenses 40 cm apart, in normal adjustment. Calculate the focal lengths of the lenses.
An astronomical telescope having a magnifying power of 8 consists of two thin lenses 45 cm apart. Find the focal length of the lenses.
Astronomial telescope has two lenses of focal power 0.5D and 20D. Then its magnifying power is:
If tube length of astronomical telescope is 105 cm and magnifying power is 20 for normal setting, calculate the focal length of objective
An astronomical telescope consists of two convex lenses of focal lengths 20 cm and 4 cm. For the nomal adjustment of the telescope, what is the angular magnification produced by the telescope ?
An astronomical telescope has a magnifying power 10. The focal length of the eye piece is 20 cm. the focal length of the objective is -