An astronomical telescope has a magnifying power of `10`. In normal adjustment, distance between the objective and eye piece is `22 cm` calculate focal length of objective lens.
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Here, `m = - 10, L = 22 cm, f_(0) = ?` As `m = -(f_(0))/(f_(e)) :. -10 = - (f_(0))/(f_(e))` or `f_(0) = 10 f_(e)` As `L = f_(0) + f_(e)` `:. 22 = 10 f_(e) + f_(e) = 11 f_(e)` or `f_(e) = (22)/(11) = 2 cm`. `f_(0) = 10 f_(e) = 10 xx 2 = 20 cm`
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