If two slits in `YDSE` have width ratio `4 : 1`, deduce the ratio of maxima and minima in the interference pattern.
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To solve the problem of finding the ratio of maxima and minima in the interference pattern created by two slits in Young's Double Slit Experiment (YDSE) with a width ratio of 4:1, we can follow these steps:
### Step-by-Step Solution:
1. **Define the Widths of the Slits**:
Let the widths of the two slits be \( W_1 \) and \( W_2 \). Given the ratio \( W_1 : W_2 = 4 : 1 \), we can express this as:
\[
W_1 = 4k \quad \text{and} \quad W_2 = k
...
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