Refractive index of air is `1.0003.` The correct thickness of air column which will have one more wavelength of yellow light `(6000 Å)` than in the same thickness in vacuum is
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Let thickness `t` of vaccume contain `n` waves and same thickness of air contain `(n + 1)` waves. `:. n = (t)/(lambda) = (t)/(6000)`, and `n + 1 = (t)/(lambda') = (t)/(lambda//mu) = (mu t)/(lambda) = (1.0003 t)/(6000)` `:. (t)/(6000) + 1 = (1.0003 t)/(6000)` `t + 6000 = 1.0003 t` `0.0003 t = 6000` `t = (6000)/(0.0003) = 2 xx 10^(7) Å = 2 mm`
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