Home
Class 12
PHYSICS
In a Young's double slit experiment, the...

In a Young's double slit experiment, the intensity of light at a point on the screen where the path difference is `lambda` is `K` units. Find the intensities at a point, where path diff. is
(i) `lambda//4` (ii) `lambda//2`.

Text Solution

Verified by Experts

From`I = I_(1) + I_(2) + 2sqrt(I_(1)I_(2)) cos phi`
if `I_(1) + I_(2) = I_(0)`, then
`I = I_(0) + I_(0) + 2 I_(0) cos phi = 2 I_(0)(1 + cos phi)`
`= 4 I_(0) cos^(2) phi//2`
When path difference is `lambda, phi = 2 pi`
`I = 4 I_(0) cos^(2) pi = 4 I_(0) = K`
(i) When path difference `= lambda//4, phi = (2pi)/(4) = pi//2`
`I = 4 I_(0) cos^(2) pi//4 = 4 I_(0)((1)/(sqrt(2)))^(2) = 2 I_(0) = (K)/(2)`
(ii) When path difference `= lambda//3, phi = 2 pi//3`
`I = 4 I_(0) cos^(2)(2 pi//3) = 4 I_(0)((1)/(2))^(2) = I_(0) = (K)/(4)`
(iii) When path difference `= (lambda)/(2), phi = pi`
`I = 4 I_(0) cos^(2) pi//2 = 0`
Promotional Banner

Topper's Solved these Questions

  • OPTICS

    PRADEEP|Exercise Very short answer question|5 Videos

  • OPTICS

    PRADEEP|Exercise very short answer questions|1 Videos

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Competition Focus (Multiple Choice Questions)|2 Videos

Similar Questions

Explore conceptually related problems

In a Young's double slit experiment , the intensity of light at a point on the screen where the path difference is lambda is k units. Find the intensity at a point where the path difference is (a) (lambda)/(4) (b) (lambda)/(3) and (c) (lambda)/(2)

In Young's double slit experiment, the intensity of light at a point on the screen where the path difference is lambda=l . The intensity of light at a point where the path difference becomes lambda//3 is

In Young's double-slit experimetn, the intensity of light at a point on the screen, where the path difference is lambda ,is I . The intensity of light at a point where the path difference becomes lambda // 3 is

In Young's double slit experiment the intensity of light at a point on the screen where the path difference lambda is K. The intensity of light at a point where the path difference is (lambda)/(6) [ lambda is the wavelength of light used] is

In Young's double slit experiment, the intensity of light at a point on the screen where path difference is lambda is I. If intensity at another point is I/4, then possible path differences at this point are

In Young's double slit experiment, the intensity on the screen at a point where path difference is lambda is K. What will be the intensity at the point where path difference is lambda//4 ?

In a Young's double slit experiment, using mono-chromatic light of wavelength lambda , the intensity of light at a point on the screen where the path defference is lambda is k units. Find the intensity at a point where the path difference is lambda//3 .

In the Young's double-slit experiment,the intensity of light at a point on the screen where the path difference is lambda is K ( lambda being the wave length of light used).The intensity at a point where the path difference is lambda/4 , will be