Two coherent monochromatic light beams of intensities I and 4 I are superposed. The maximum and minimum possible intensities in the resulting beam are
Text Solution
Verified by Experts
Here, `I_(1) = I and I_(2) = 4 I` As source are coherent, `:. I = I_(1) + I_(2) + 2sqrt(I_(1)I_(2)) cos phi` When `phi = 0`, intensity is maximum `:. I_(max) = I + 4 I + 2 sqrt(I xx 4 I) = 9 I` When `phi = pi`, intensity is minimum `:. I_(min) = I + 4 I + 2sqrt(I xx 4I) cos pi` `= 5 I - 4 I = I`
Topper's Solved these Questions
OPTICS
PRADEEP|Exercise Very short answer question|5 Videos
OPTICS
PRADEEP|Exercise very short answer questions|1 Videos
Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are
Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are
Two coherent monochromatic light beam of intensitites I and 4I are superposed.The maximum and minimum possible intensities in the resulting beam, is
Two coherent monochromatic light beams of intensities 4/ and 9/ are superimosed the maxmum and minimum possible intenties in the resulting beam are
Two coherent monochromatic light beams of amplitude 3 and 5 units are superposed . The maximum and minimum possible intensities in the resulting beams are in the ratio