If the two slits in Young's experiment have width ratio `1 : 4`, deduce the ratio of intensity at maxima and minima in the intereference pattern.
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To solve the problem of finding the ratio of intensity at maxima and minima in Young's double-slit experiment with slits having a width ratio of 1:4, we can follow these steps:
### Step 1: Define the Widths of the Slits
Let the width of the first slit be \( W_1 = 4a \) and the width of the second slit be \( W_2 = a \), where \( a \) is a constant.
### Step 2: Calculate the Amplitudes
The amplitude of the wave from each slit is proportional to the square root of the width of the slit. Therefore, the amplitudes can be defined as:
- Amplitude from slit 1: \( A_1 = \sqrt{W_1} = \sqrt{4a} = 2\sqrt{a} \)
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