In Young's double slit experiment, the two slits `0.15 mm` apart are illuminated by light of wavelength `450 nm`. The screen is `1.0 m` away from the slits. Find the distance of second bright fringe and second dark fringe from the central maximum. How will the fringe pattern change if the screen is moved away from the slits ?
Text Solution
AI Generated Solution
To solve the problem, we will use the formulas for the positions of bright and dark fringes in Young's double slit experiment.
### Step-by-Step Solution:
1. **Identify the Given Values:**
- Distance between the slits (d) = 0.15 mm = \(0.15 \times 10^{-3}\) m
- Wavelength of light (λ) = 450 nm = \(450 \times 10^{-9}\) m
- Distance from the slits to the screen (D) = 1.0 m
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