Find the intensity at a point on a screen in YDSE, where the interfering waves of equal intensity have a path difference of (i) `lambda//4` (ii) `lambda//3`.
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AI Generated Solution
To find the intensity at a point on a screen in the Young's Double Slit Experiment (YDSE) where the interfering waves of equal intensity have a path difference of \( \frac{\lambda}{4} \) and \( \frac{\lambda}{3} \), we can follow these steps:
### Step 1: Understand the formula for intensity in YDSE
The intensity \( I \) at a point where two waves of equal intensity \( I_0 \) interfere is given by the formula:
\[
I = 4I_0 \cos^2\left(\frac{\Delta \phi}{2}\right)
\]
where \( \Delta \phi \) is the phase difference between the two waves.
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