In YDSE, when the entire apparatus is immersed in water, what happens to fringe width ?
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To solve the problem regarding the change in fringe width when the entire Young's Double Slit Experiment (YDSE) apparatus is immersed in water, we can follow these steps:
### Step-by-Step Solution:
1. **Understanding Fringe Width**:
The fringe width (β) in Young's double slit experiment is given by the formula:
\[
\beta = \frac{\lambda D}{d}
...
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In young's double slit experiment the slits are illumated by light of wavelength 5890^(@) A and the distance between the fringes obtained on the screen is 0.2^(@) . If the whole apparatus is immersed in water then the angular fringe width will be, if the refractive index of water is 4//3
In Youngs 's double slit experiment, the fringe width obtained by using monochromatic light of wavelength 6000 Å is 2 mm. if the whole apparatus is immersed in water of R.I. 1.33, then the change in fringe width will be
Assertion (A) : If the whole apparatus of YDSE is immersed in a liquid, then the fringe width will decrease Reason (R ) : The wavelength of light in water is more than that of air.
In Young's experiment , the fringe width of the fringes with light of wavelength 6000 Å is 2.0 mm . What will be the fringe width if the entire apparatus is immersed in a liquid of refractive index 1.33 ?
In a double slit experiment the angular width of a fringe is found to be 0.2^(@) on a screen placed I m away. The wavelength of light used in 600 nm. What will be the angular width of the fringe if the entire experimental apparatus is immersed in water ? Take refractive index of water to be 4//3 .
In Young's experiment, the fringe width is 3 mm for a light of wavelength 6000Å . If the entire apparatus is dipped in water of R.I. 3/2 , then what is the change in fringe width?
