Light of wavelength `5000Å` is diffrated by an aperture of width `2mm`. For what distance by the diffracted beam does the spreading due to diffraction become greater than the width of the aperture ?
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Here, `lambda = 5000Å = 5 xx 10^(-7)m, a = 2mm = 2 xx 10^(-3)m, Z_(F) = ?` As Fresnel distance, `Z_(F) = (a^(2))/(lambda) :. Z_(F) = (2 xx 10^(-3))^(2)/(5 xx 10^(-7)) = (40)/(5) = 8 m`
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