Light of wavelength `600 nm` is incident on an aperture of size `2 mm`. Calculate the distance light can travel before its spread is more than the size of aperture.
Text Solution
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Here, `lambda = 600 nm = 6 xx 10^(-7)m`, `a = 2mm = 2 xx 10^(-3)m` The required distance is Fresnel distance `Z_(F) = (a^(2))/(lambda) = (2 xx 10^(-3))^(2)/(6 xx 10^(-7)) = 6.67 m`
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