A parallel beam of light of `600 nm` falls on a narrow slit and the resulting diffraction pattern is observed on a screen `.12 m` away. It is observed that the first minimum is at a distance of `3 mm` from the centre of the screen. Calculate the width of the slit.
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Here, `lambda = 5000 Å = 600 nm = 6 xx 10^(-7)m`, `D = 1.2 m, n = 1, x = 3 mm = 3 xx 10^(-3) m, a = ?` For first minimum, `a sin theta = n lambda` `a. ((x)/(D)) = 1 lambda` `a = (lambda D)/(x) = (6 xx 10^(-7) xx 1.2)/(3 xx 10^(-3)) = 2.4 xx 10^(-4)m = 0.24 mm`
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