A screen is placed `2m` away from the single narrow slit. Calculate the slit width if the first minimum lies `5 mm` on either side of the central maximum. Incident plane waves have a wavelength of `5000 Å`.
Text Solution
AI Generated Solution
To solve the problem, we will use the formula for the position of the first minimum in a single-slit diffraction pattern. The position of the first minimum is given by:
\[
y = \frac{\lambda D}{d}
\]
where:
- \( y \) is the distance from the central maximum to the first minimum,
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