Calculate the resolving power of a microscope with cone angle of light falling on the objective equal to `60^(@)`. Take `lambda = 600 nm mu` for air `= 1`.
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Here, `2 theta = 60^(@), theta = 30^(@)`, `lambda = 600 nm = 6 xx 10^(-7) m , mu = 1` `R.P. = (1)/(d) = (2 mu sin theta)/(lambda)` `R.P. = (2 xx 1 xx sin 30^(@))/(600 xx 10^(-9)) = (10)/(6) xx 10^(6) = 1.67 xx 10^(6)`
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