The diameter of the pupil of human eye is about `2 mm`. Human eye is most sensitive to the wavelength `555 nm`. Find the limit of resolution of human eye.

Explanation

Here, `D = 2 mm = 2 xx 10^(-3)m`
`lambda = 555 nm = 555 xx 10^(-9)m`
Limit of resolution,
`dtheta = (1.22 lambda)/(D) = (1.22 xx 555 xx 10^(-9))/(2 xx 10^(-3))`
`= 3.39 xx 10^(-4)rad`
`dtheta = 3.39 xx 10^(-4) xx ((180)/(pi))^(@)`
`= 0.0194^(@) = 0.0194 xx 60 min = 1.2 min`