If the angle between the pass axis of polariser and analyser is `45^(@)`, write the ratio of intensities of original light and the transmitted light after passing through analyser.
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Let original intensity of unpolarised light be `I_(0)` Inyensity of polarised light transmitted from polariser `= (I_(0))/(2)` As `theta = 45^(@)`, `:.` Intensity of polarised light transmitted from analyser `= (I_(0))/(2) cos^(2) 45^(@) = (I_(0))/(2) xx ((1)/(sqrt(2)))^(2) = (I_(0))/(4)` The required ratio `= (I_(0))/(I_(0)//4) = 4 : 1`
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