If the angle between the pass axis of polariser and analyser is `45^(@)`, write the ratio of intensities of original light and the transmitted light after passing through analyser.
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From Law of Malus, `I = I_(0) cos^(2) theta` `(I_(0))/(I) = (I)/(cos^(2) theta) = (1)/(cos 45^(@))^(2) = (1)/(1//sqrt(2))^(2) = 2`
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