In a single slit diffraction experiment, the width of the slit is made double the original width. How does this affect the size and intensity of the central diffraction band ?

Explanation

The width of central maximum in signle slit diffraction experiment is
`2x = ( 2D lambda)/(a) = (2 f lambda)/(a)`
When width of slit `(= a)` is doubled, the size of central diffraction band will become half. Area of central diffraction band will become `(1//4)th` and hence its intensity would become `4 times`. The plot of intensity distribution is shwon in Fig. The dotted line curve is when width of slit doubled.