A small telescope has an objective lens of focal length `140 cm` and eye piece of focal length `5.0 cm`. What is the magnifying power of telescope for viewing distant objects when (a) the telescope is in normal adjustment (i.e. when the image is at infinity) (b) the final image is formed at the least distance of distinct vision `(25 cm)`.
Text Solution
AI Generated Solution
To solve the problem step by step, we will calculate the magnifying power of the telescope in two different scenarios as described in the question.
### Given:
- Focal length of objective lens (F_o) = 140 cm
- Focal length of eyepiece (F_e) = 5.0 cm
- Least distance of distinct vision (D) = 25 cm
### (a) Magnifying Power in Normal Adjustment (Image at Infinity)
...
Topper's Solved these Questions
OPTICS
PRADEEP|Exercise Very short answer question|5 Videos
OPTICS
PRADEEP|Exercise very short answer questions|1 Videos
A small telescope has an objective lens of focal length 140 cm and an eyepiece of focal length 5.0 cm. what is the magnifying power of the telescope for viewing distant objects when (a) the telescope is in normal adjustment (i.e, when the final image is at infinity ), (b) The final image is formed at the least distance of distinct vision (25 cm )
A small telescope has an objective lens of focal length 150 cm and an eye piece of focal length 6.0 cm. The magnifying power of the telescope for distinct vision adjustment is:
A telescope has an objective of focal length 100 cm and an eye-piece of focal length 5 cm. What is the magnifying power of the telescope when it is in normal adjustment?
A small telescope has an objective lens of focal length 144 cm and an eye-piece of focal length 6.0 cm . What is the magnifying power of the telescope ? What is the separation between the objective and the eye-piece ?
A telescope has an objective of focal length 100 cm and an eyepiece of focal length 5 cm. What is the magnifying power of the telescope when the final image is formed at the least distance of distinct vision ?