In Young's experiement, the distance between slits is `0.28mm` and distance between slits and screen is `1.4m`. Distance between central bright fringe and third bright fringe is `0.9cm`. What is the wavelength of used light?
Text Solution
Verified by Experts
Here, `d = 0.28 mm = 0.28 xx 10^(-3)m, D = 1.4 m, x = 1.2 cm = 1.2 xx 10^(-2)m, n = 4, lambda = ?` For constructive interference `x = n lambda = (D)/(d) or lambda = (x d)/(nD) = (1.2 xx 10^(-2) xx 0.28 xx 10^(-3))/(4 xx 1.4) = 6 xx 10^(-7)m`
Topper's Solved these Questions
OPTICS
PRADEEP|Exercise Very short answer question|5 Videos
OPTICS
PRADEEP|Exercise very short answer questions|1 Videos
In Young's double slit experiment, the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be
In young's double slit experiment, if the distance between the slits is halved and the distance between the slits and the screen is doubled, the fringe width becomes
In a Young's double-slit experiment , the slits are separated by 0.28 mm and screen is placed 1.4 m away . The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm . Determine the wavelength of light used in the experiment .
In Young's double-slit experiment, the separation between the slits is halved and the distance between the slits and the screen in doubled. The fringe width is
In Young's double-slit experiment, a screen is placed 1.5 m away from slits which are 0.03 cm apart. The distance between the central bright fringe and fourth bright fringe is 1 cm. Calculate the wavelength of light used.
In Young's double slit experiment, the slits are 0.2 mm apart and the screen is 1.5 m away. It is observed that the distance between the central bright fringe and fourth dark fringe is 1.8 cm . Calculate wavelength of light used.
In the Young's experiment, the distance between slit and screen is doubled and the distance between the two slits is reduced to half. The fringe widht is