In Young's double slit experiment, the intensity of light at a point on the screen where the path difference is `lambda=l`. The intensity of light at a point where the path difference becomes `lambda//3` is
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Let `I_(1) = I_(2) = I`. If `phi` is phase difference between the two light waves, then resultant intensity. `I_(R ) = I_(1) + I_(2) + 2 sqrt(I_(1)I_(2)) cos theta` When path difference `= lambda`, phase diff. `phi = 0^(@) :. I_(R ) = I + I + 2sqrt(I I) cos 0^(@) = 4 I = K` When path difference `= (lambda)/(3)`, phase diff. `phi = (2pi)/(3)rad. :. I'_(R ) = I + I + 2sqrt(I I) "cos" (2pi)/(3)` `I'_(R ) = 2I + 2I = (-(1)/(2)) = I = K//4`
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