Home
Class 12
PHYSICS
In double slit experiment using light of...

In double slit experiment using light of wavelength `600 nm`, the angular width of a fringe formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?

Text Solution

AI Generated Solution

To solve the problem of finding the spacing between the two slits in a double slit experiment, we will follow these steps: ### Step 1: Understand the relationship between angular width, wavelength, and slit spacing In a double slit experiment, the angular width (θ) of the fringe is related to the wavelength (λ) of the light and the spacing between the slits (d) by the formula: \[ \theta = \frac{\lambda}{d} \] Where: ...
Promotional Banner

Topper's Solved these Questions

  • OPTICS

    PRADEEP|Exercise Very short answer question|5 Videos
  • OPTICS

    PRADEEP|Exercise very short answer questions|1 Videos
  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Competition Focus (Multiple Choice Questions)|2 Videos

Similar Questions

Explore conceptually related problems

In Young's double slit experiment, the angular width of a fringe formed on a distant screen is 0.1^(@) . What is the spacing between the slits, if the waveelngth of light used is 6000 Å?

In Young's double-slit experiment the angular width of a fringe formed on a distant screen is 1^(@) . The wavelength of light used is 6000 Å . What is the spacing between the slits?

In a Young's double slit esperiment, the angular width of a fringe formed on a distant screen is 1^(@) . The slit separation is 0.01 mm. The wavelength of the light is

In young's double-slit experiment , the spacing between the slits is 'd' and the wavelength of light used is 6000Å If the angular width of a fringe formed on a distance screen is 1^@ then calculate 'd' .

In a Young's double slit experiment, bi-chromatic light of wavelengths 400 nm and 560 nm are used. The distance between the slits is 0.1 mm and the distance between the plane of the slits and the screen is 1m. The minimum distance between two successive regions of complete darkness is

In Young's double slit experiment, while using a source of light of wavelength 4500 Å , the fringe width obtained is 0.4 cm. If the distance between the slits and the screen is reduced to half , calculate the new fringe width.

State two conditions to obtain sustained interference of light. In young's double slit experiment, using light of wavelength 400 nm, interference fringes of width X are obtained. The wavelength of light is increased to 600 nm and the separation between the slits is halved. if one wants the observed fringe width on the screen to be the same in the two cases, find the ratio of the distance between the screen and the plane of the slits in the two arrangements.