Statement - I : Reflection result in a plane polarised light, if the light is incident on the interface from the side with higher refractive index. Statement - II : Brewster's angle is less than critical angle.
Text Solution
Verified by Experts
Yes, reflection can result if the light, is incident on the interface from the side with higher refractive index. As is known, polarization by reflection occurs when angle of incidence is the Brewster's angle `(i_(p))`. i.e., `tan i_(p) = n = (n_(2))/(n_(1))` where `n_(2) gt n_(1)`. When light travels in such medium, the critical angle `c` is such that `sin c = (1)/(n) = (n_(1))/(n_(2))` where `n_(2) gt n_(1)` As `|tani_(p)|gt|sin c|` for large angles, therefore, `i_(p) gt c` Hence polarization by reflection shall occur definitely.
Topper's Solved these Questions
OPTICS
PRADEEP|Exercise Very short answer question|5 Videos
OPTICS
PRADEEP|Exercise very short answer questions|1 Videos
Can reflection result in plane polarised light if the light is incident on interface from the side with higher refractive index?
Statement - I : Reflection results in plane front the side with higher refractive index. Statement - II : Brewster's angle is less than critical angle.
A ray of light is incident on the surface of plate of glass of refractive index 1.5 at the polarising angle. The angle of refraction of the ray will be
A ray of light is incident on the surface of a glass plate of refractive index 1.6 at polarzing angle. Calculate the angles of reflection and refraction.
Light in air is incident on a plastic plate at the Brewster angle. The angle of refraction is 35.0^(@) Determine the Brewster angle.
When unpolarised light is incident on the interface separating the rarer medium and the denser medium, Brewster angle is found to be 60^(@) . Determine the refractive index of the denser medium.
AN unpolarised beam of light is incident at the polarising angle on the surface of a transparent medium of refractive index 1.6. The angle of refraction in the medium is
An upolarized light beam is incident on a surface at an angle of incidence equal to Brewster's angle. Then,
A ray of light inwater is incident on its surface open to air.The angle of incidence is theta ,which less than the critical angle.Then there will be-